Two particles undergoing SHM of the same amplitude and frequency along the same straight line. They pass one another when going in opposite directions. Each time their displacement is half of their amplitude. What is the phase difference between them?
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
D
No detailed text explanation provided yet.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
For a simple pendulum, the graph between and is a
In simple harmonic motion, the particle is
A simple harmonic oscillator has a period of 0.01 s and an amplitude of 0.2 m. The magnitude of the…
At a particular position, the velocity of a particle in SHM with amplitude a is times the velocity…
The particle is executing SHM on a 4 cm long line. If its velocity at mean position is , its frequ…
The velocity-time diagram of a harmonic oscillator is shown in the figure. The frequency of oscilla…